| 喻凤香.化学计量法结合气相色谱鉴别米糠油掺伪菜籽油[J].中国油脂,2014,39(12):.[YU Fengxiang.Chemometrics approach combined with gas chromatography for identification of rice bran oil adulterated with rapeseed oil[J].China Oils and Fats,2014,39(12):.] |
| 化学计量法结合气相色谱鉴别米糠油掺伪菜籽油 |
| Chemometrics approach combined with gas chromatography for identification of rice bran oil adulterated with rapeseed oil |
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| DOI： |
| 中文关键词: 米糠油 菜籽油 掺伪 检测 化学计量法 气相色谱 |
| 英文关键词:rice bran oil rapeseed oil adulteration determination chemometrics approach gas chromatography |
| 基金项目: |
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| 摘要点击次数: 1228 |
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| 中文摘要: |
| 为研究米糠油掺伪菜籽油的快速定性定量检测方法，采用毛细管气相色谱法测定掺伪不同比例菜籽油的米糠油脂肪酸含量，将C14∶0、C16∶0、C16∶1、C17∶0、C18∶0、C18∶1、C18∶2、C18∶3、C20∶0、C20∶1、C22∶1含量作为变量，通过聚类分析和判别分析对掺伪油样进行定性分析，采用一元线性法与指纹图谱相似度法对掺伪油样进行定量分析。结果表明：米糠油掺伪菜籽油2%以上，聚类分析和判别分析均能正确进行辨别；特征脂肪酸一元线性模型为YC22∶1=0.158 2X+0.350 7（R2=0.991 0），检出限为2%；利用向量夹角余弦法计算纯米糠油与掺伪米糠油的相似度，建立的掺伪量与相似度的线性模型为Y=-23.62X3-8.380 6X2-6.138 3X+100.12（R2=0.999 4）。 |
| 英文摘要: |
| To establish a rapid qualitative and quantitative detection method of rice bran oil（RBO） adulterated by rapeseed oil，pure RBO and adulterated RBO with different proportions of rapeseed oil were detected by capillary gas chromatography. Using contents of C14∶0，C16∶0，C16∶1，C17∶0，C18∶0，C18∶1，C18∶2，C18∶3，C20∶0，C20∶1 and C22∶1 as variables，qualitative detection was made by cluster analysis and discriminant analysis and quantitative detection was made by the linear method and chromatographic fingerprint similarity method. The results showed that cluster analysis and discriminant analysis were able to make correct identification when RBO was mixed with more than 2% rapeseed oil. Linear model of characteristic fatty acid（Y） and adulteration amount（X） of rapeseed oil was established as follows：YC22∶1=0.158 2X+0.350 7（R2=0.991 0）and the limit of detection was 2%. The vectorial angle method（VAM） was brought forward to calculate similarity of chromatographic fingerprint between adulterated RBO and pure RBO，and the fitting model of similarity （Y） and adulteration amount（X）was Y=-23.62 X3-8.380 6X2-6.138 3X+100.12（R2=0.999 4）. |
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